2x^2/2+5x/4=-3/4

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Solution for 2x^2/2+5x/4=-3/4 equation: 


x in (-oo:+oo)

(2*x^2)/2+(5*x)/4 = -3/4 // + -3/4

(2*x^2)/2+(5*x)/4-(-3/4) = 0

(2*x^2)/2+(5*x)/4+3/4 = 0

x^2+5/4*x+3/4 = 0

DELTA = (5/4)^2-(3/4*1*4)

DELTA = -23/16

DELTA < 0

x belongs to the empty set

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